A 12 member jury for a criminal case will be selected from a pool of 15 men and 15 women. What is the probability that the jury will have 6 men and 6 women?
To find this, we need to know the number of ways the jury can be picked overall, and then the number of ways 6 men and 6 women can be on the jury. The fraction of the two will be the probability.
The total number of ways the jury can be picked is the combination of a pool of 30 people and choosing 12:
and now let's evaluate this:
Ok - we know the number of ways the jury can be picked. Now how many ways can the jury consist of 6 men and 6 women?
For the men, there are 15 in the pool and we're picking 6:
and now let's evaluate that:
The same number of choices of women are available, so we multiply the number of men's choices and women's choices:
And now we can find the probability:
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The probability that the jury will have 6 men and 6 women is 0.1966, or approximately 19.66%.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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