What is the formal charge on the #Br# and #O# atoms in the #BrO_3^-# ion?

Answer 1

#2xx# #Br=O# bonds, and #1# #xx# #Br-O^-# bond. One #O# atom bears a negative charge, and the remaining atoms are neutral.

The conventional Lewis structure of bromate ion is #(O=)_2Br-O^-#. Around the doubly bound oxygens there are 6 electrons (hence #O# is neutral); around bromine there are 7 electrons (4 from the doubly bound oxygens, 1 from the singly bound oxygen and 2 from the lone pair); and around the charged oxygen, there are (necessarily) 7 electrons (one from the #Br-O# bond and 6 lone pair electrons), so this centre (formally) has a negative charge.

It should be noted that an atom's formal charge is determined by the number of electrons surrounding it; lone pairs only devolve to the atom in question, whereas single bonds share electrons among the bound atoms.

Naturally, each oxygen atom is equal in the actual molecule.

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Answer 2

The formal charge on the Br atom is +1, and on the O atoms is -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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