What is the formal charge on each atom in the tetrahydridoborate ion?

Answer 1

Well, we normally represent sodium borohydride as #Na^+BH_4^-#...

...and since this is clearly NEUTRAL...we split the salt up in to #Na^+# and #BH_4^(-)# ions....
...for the tetrahedral borohydride ion....there are #4xxB-H# bonds....each hydrogen atom is associated with ONE electron, and is therefore neutral. On the other hand, the boron atom get 4 electrons from the #B-H# bonds, and there are two inner core electrons....six electrons in total. Since for boron, #Z=5#, given 5 nucular charges, and SIX electronic charges....the boron atom has a formal negative charge.
Borohydrides ACT as hydride transfer reagents in their reaction chemistry....i.e. #BH_4^(-)-=BH_3 + H^-#...they tend to be a bit milder reagents than aluminum hydrides...salts of #AlH_4^(-)#...
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Answer 2

Boron: -1 Hydrogens: 0

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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