In triangle ABC, <A=84.2°, <B=20.7°, B=17.2, how do you find side C?

Answer 1

Solve triangle knowing A = 84.2; B = 20.7 and b = 17.2.

Ans: c = 47.67

Apply the sin Laws: #b/sin B = c/sin C.# First, find angle C. C = 180 - A - B = 180 - 84.2 - 20.7 = 75.1 #c/sin 75.1 = 17.2/sin 20.7#

#c = 17.2(0.97/0.35) = 47.67#

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Answer 2

Anna Andrews

To find side $c$ of triangle $ABC$ , you can use the Law of Sines:

$\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}$

Given $\angle A = 84.2^\circ$ , $\angle B = 20.7^\circ$ , and $b = 17.2$ , you can find $\angle C$ using the fact that the sum of angles in a triangle is $180^\circ$ :

$\angle C = 180^\circ - \angle A - \angle B$

Once you have $\angle C$ , you can use the Law of Sines to find side $c$ .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

In triangle ABC, &lt;A=84.2°, &lt;B=20.7°, B=17.2, how do you find side C?

In triangle ABC, <A=84.2°, <B=20.7°, B=17.2, how do you find side C?