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How do you simplify –| –2 |2? | HIX Tutor

FIrst, process the term within the <a href="https://socratic.org/algebra/linear-inequalities-and-absolute-value/absolute-value">absolute value</a> function:
<mathjax>#-color(red)(abs(-2))2 =&gt; -(2)2#</mathjax>
Next, process the multiplication of the two <mathjax>#2#</mathjax> terms:
<mathjax>#-(2)2 =&gt; -(color(red)(2) * 2) =&gt; -(4) =&gt; -4#</mathjax>

FIrst, process the term within the absolute value function:
<mathjax>#-color(red)(abs(-2))2 =&gt; -(2)2#
Next, process the multiplication of the two <mathjax>#2#</mathjax> terms:
<mathjax>#-(2)2 =&gt; -(color(red)(2) * 2) =&gt; -(4) =&gt; -4#

See the entire solution process below:

Eva Abramson

To simplify –| –2 |2, first evaluate the absolute value of –2, which is 2. Then, apply the negative sign outside the absolute value, making it -2. Finally, square -2 to get 4. The simplified form is 4.

How do you simplify #–| –2 |2#?