How do you graph #y

Question

How do you graph #y<3x-3/4# on the coordinate plane?

Avery Alexander · Accepted Answer

See a solution process below:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality. For: #x = 0# #y = (3 * 0) - 3/4# 2y = 0 - 3/4# #y = -3/4# or #(0, -3/4)# For: #x = 1# #y = (3 * 1) - 3/4# #y = 3 - 3/4# #y = (4/4 * 3) - 3/4# #y = 12/4 - 3/4# #y = 9/4# or #(1, 9/4)# We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality. graph{(x^2+(y+(3/4))^2-0.035)((x-1)^2+(y-(9/4))^2-0.035)(y-3x+(3/4))=0 [-10, 10, -5, 5]} Now, we can shade the right side of the line to represent the inequality. The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause. graph{(y-3x+(3/4)) < 0 [-10, 10, -5, 5]}

Eva Abramson · Answer

undefined To graph y < 3x - 3/4 on the coordinate plane, first graph the boundary line y = 3x - 3/4 as a dashed line. Then, shade the region below the line because y is less than 3x - 3/4.

How do you graph #y&lt;3x-3/4# on the coordinate plane?

How do you graph #y<3x-3/4# on the coordinate plane?