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How do you factor the trinomial #x^2+6x+5#?

Answer 1

Savannah Anderson

#(x+1)(x+5)#

#x^2+5x+1x+5# two numbers that MULTIPLY to 5, ADD to 6 #x(x+5)+1(x+5)# find common factor #(x+1)(x+5)#

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Answer 2

Isaiah Anthony

To factor the trinomial $x^2 + 6x + 5$ , you need to find two numbers that multiply to $5$ and add up to $6$ . These numbers are $1$ and $5$ . Then, rewrite the middle term using these numbers:
$x^2 + 6x + 5 = x^2 + x + 5x + 5$

Next, factor by grouping:
$= (x^2 + x) + (5x + 5)$
$= x(x + 1) + 5(x + 1)$

Now, you can see that both terms have a common factor of $(x + 1)$ . Factor out the common factor:
$= (x + 1)(x + 5)$

So, the factored form of $x^2 + 6x + 5$ is $(x + 1)(x + 5)$ .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.