How do you factor #2x^2-21x-11#?
a × b = -22 a + b = -21
By inspection (or trial ad error) we can find two numbers a=-22 and b=1
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To factor the quadratic expression 2x^2 - 21x - 11, we need to find two numbers that multiply to give us (2 * -11) = -22 and add to give us -21. These numbers are -22 and 1. Then, we rewrite the middle term using these numbers, which gives us 2x^2 - 22x + x - 11. Now, we factor by grouping, taking out the common factors from the first two terms and the last two terms separately. This gives us 2x(x - 11) + 1(x - 11). Finally, we factor out the common factor (x - 11), which leaves us with the factored form: (2x + 1)(x - 11).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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