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How can I draw two achiral isomers of 3,4,5-trimethylheptane?

Answer 1

You must draw structures that have an internal mirror plane.

The only two possibilities are:

(#3S,4s,5R#)-3, 4, 5-trimethylheptane

They each have an internal plane of symmetry that is perpendicular to the plane of the paper and bisects the atoms of the #"CH"_2# group at #"C"-4#.

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Answer 2

Maya Allen

To draw two achiral isomers of 3,4,5-trimethylheptane, you would draw two structures where the three methyl groups are positioned in a way that the molecule has a plane of symmetry, making it achiral. One possible arrangement is 3,4,5-trimethylheptane with all three methyl groups on the same side of the carbon chain, and the other isomer is 3,4,5-trimethylheptane with two methyl groups on one side and the third on the opposite side of the chain.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.