What is the Lewis structure of #SO_2#?

Answer 1

Well, we could write...#""^(-)O-ddotS^+=O#

...which gives a bent structure, where #/_O-S-O=119^@#.

Sulfur has a formal positive charge because it has five valence electrons around it instead of six. Formally singly-bound oxygen has seven valence electrons around it, so it has a FORMAL negative charge. Of course, you can draw the resonance isomer that equates the oxygen atoms.

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Answer 2

O=S=O is the Lewis structure of SO2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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