Write a nuclear reaction for the neutron-induced fission of U−235 to produce Te−137 and Zr−97. please help?

You are aware that a neutron, a subatomic particle with a mass roughly equal to that of a proton and no electric charge, must collide with the nucleus of uranium-235.

You'll use those as rectants.

Writing about isotopes takes the form

Examine a periodic table to determine the atomic number of each of the three isotopes involved in the reaction.

You now possess the necessary items to compose the nuclear equation.

By keeping the mass numbers equal, you can calculate the amount of neutrons that will be released by the reaction: 235 + 1 for the reactants and 137 + 97 +? for the products.

Thus, it follows that

With 92 + 0 on the reactant side and 52 + 40 on the product side, the atomic numbers are already balanced.

As a result, for this reaction, the balanced nuclear equation is

Sure, here is the nuclear reaction for the neutron-induced fission of U-235 to produce Te-137 and Zr-97:

$_{92}^{235}\textrm{U} + _0^1\textrm{n} \rightarrow _{52}^{137}\textrm{Te} + _{40}^{97}\textrm{Zr} + 2 _0^1\textrm{n}$