Why is glucose soluble in water but cyclohexane is not?
The main reason is that the former contains an -OH group whereas the latter does not.
Because glucose contains oxygen, it has five -OH groups, which greatly aid in its ability to form bonds with water (-H). Additionally, glucose is soluble in water.
Since cyclohexane lacks an -OH group, it cannot form a bond with a -H ion and is therefore insoluble in water.
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Glucose is soluble in water due to hydrogen bonding between its hydroxyl groups and water molecules. Cyclohexane lacks polar groups, preventing it from forming significant interactions with water, resulting in insolubility.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- Why is the chair the most stable conformation in the cyclohexanes?
- Why do homodesmotic reactions give more accurate estimates of the intrinsic strain and the cyclic delocalization?
- What is so special about the chair conformation?
- What is the molecular formula for hexane, cyclohexane, and toluene?
- What is the condensed structural formula for cyclohexane?
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