What is the taylor series in sigma notation of: #sin^2(x)#?
Keep in mind here that 0!=1, so the case of n=0 is still valid.
thus we get:
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The Taylor series in sigma notation for ( \sin^2(x) ) is:
[ \sin^2(x) = \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n)!}x^{2n} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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