What is the relationship between the pOH and the OH- ion concentration of a solution?

Answer 1

#pOH=-log_10[HO^-]#

Additionally, the acid-base equilibrium functions in aqueous solution:

#2H_2OrightleftharpoonsH_3O^(+) + HO^-#
At #298*K#, #K_w=10^-14=[HO^-][H_3O^+]#
And taking negative #log_10# of both sides.............
#-log_10K_w=-log_(10)10^-14=-log_10[HO^-]-log_10[H_3O^+]#
i.e. #14=pH+pOH#.
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Answer 2

The relationship between the pOH and the concentration of hydroxide ions (OHOH^-) in a solution is inverse. That is, as the pOH decreases, the concentration of OHOH^- ions increases, and vice versa. This relationship is defined by the equation:

pOH=log[OH]pOH = -\log[OH^-]

Where [OH][OH^-] represents the concentration of hydroxide ions in moles per liter (M). Therefore, a lower pOH value indicates a higher concentration of OHOH^- ions, while a higher pOH value indicates a lower concentration of OHOH^- ions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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