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What is the Lewis dot structure of #"H"_2"O"_2#?

Answer 1

It is simply #H-O-O-H#, a neutral molecule, in which each #O# bears #2# lone pairs of electrons.

There are 14 valence electrons to distribute, 4 of these are conceived to constitute the #H-O# bond, 2 of these the #O-O# bond, and the 8 remaining are the 4 formal lone pairs on the oxygen atoms.

The oxidation state of oxygen in this molecule is #-I#; in fact this is why it is called a #"peroxide"#. Why does #O# bear this formal oxidation state? For contrast, the oxidation of #O# in water is certainly #-II#.

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Answer 2

Elias Aguila

The Lewis dot structure of H2O2 is:

H-O-O-H

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.