What is the intensity of a sound which has a sound level of 35 dB?

Answer 1

You can use the relationship: #I(dB)=10log(I/I_0)# Where #I_0=10^(-12) W/m^2# represents the intensity just audible (correspnding to #0 dB#). So: #35=10log(I/10^(-12))#; power #10# both sides and rearrange: #I=3.2xx10^-9 W/m^2#

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Answer 2

Emily Abbate

To find the intensity of a sound given its sound level in decibels (dB), you can use the formula:

Intensity = 10^((Sound Level in dB - Reference Sound Level) / 10)

In this case, the reference sound level is typically 0 dB, representing the threshold of human hearing. So, if the sound level is 35 dB:

Intensity = 10^((35 dB - 0 dB) / 10)
= 10^(35 / 10)
≈ 3.162 × 10^-3 watts per square meter (W/m^2)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.