What is the Cartesian form of #( 7 , (25pi)/12 ) #?
So in this particular case we get
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The Cartesian form of the point (7, (25π)/12) is given by: [ (7 \cos((25π)/12), 7 \sin((25π)/12)) ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the area of the region bounded by the polar curves #r^2=cos(2theta)# and #r^2=sin(2theta)# ?
- What is the equation of the tangent line to the polar curve # f(theta)=theta^2costheta-theta+tan(theta/3) # at #theta = pi#?
- What is the distance between the following polar coordinates?: # (1,(7pi)/12), (3,(9pi)/8) #
- What is the equation of the tangent line to the polar curve # f(theta)=2thetasin(theta)+thetacot^2(4theta) # at #theta = pi/3#?
- What is the equation of the tangent line to the polar curve #f(theta)=theta- sin((3theta)/2-pi/2)+tan((2theta)/3-pi/2) # at #theta = pi#?

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