What equation do astronomers use to calculate the sun-earth distance?

Answer 1

The Easiest is S = V . t

The Easiest way to get the distance between the Sun and the Earth is using the Equation of Motion. S = V.t. For this we need the Time that a Photon takes to reach Earth from the Sun's Surface and the Speed of light in Vacuum. Once we have these we can put these in the distance equation. Below is how it works.

The Time that a photon takes from the Surface of the Sun to Reach Earth = t = 8 minutes and 19 seconds = 499 seconds.

Speed of Light in Vacuum = V = 300,000 km/ sec.

Distance = V . t Distance = 300000 x 499 Distance = 149,700,000 km Distance = 149 Million Km.

Please note that this is the average distance between the Sun and the Earth since the Orbit is an ellipse so the time for a Photon to reach Earth also changes with distance and Vice Versa.

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Answer 2

The Earth Sun distance is determined using Kepler's 3rd law.

Kepler's 3rd law relates a planets orbital period #T# in years to its semi-major axis distance #a# in AU.
#T^2=a^3#

By observing the positions of the planets we can easily determine the orbital periods for them in AU.

Now we need one more piece of information to determine the actual length of an AU. The easiest way of doing this is to find the distance between Earth and Venus. This was originally done using parallax. Now we can measure the distance to a high degree of accuracy using radar. Radio waves are bounced off Venus and the time taken for the return journey gives the distance.

Using Kepler's law we know that Venus is 0.73 AU from the Sun. So, the distance between Earth and Venus is 0.27 AU. Using measurements we can determine that the distance between Earth and Venus is about 42,000,000km. From that we can determine that 1AU, which is the distance of the Earth from the Sun, is about 150,000,000km.

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Answer 3

Astronomers use the equation known as Kepler's third law of planetary motion, which relates the orbital period of a planet to its distance from the sun. The equation is:

[ T^2 = \frac{{4 \pi^2}}{{G(M_1 + M_2)}} r^3 ]

Where:

  • ( T ) is the orbital period of the planet,
  • ( G ) is the gravitational constant,
  • ( M_1 ) and ( M_2 ) are the masses of the two objects (in this case, the sun and the Earth),
  • and ( r ) is the average distance between the sun and the Earth.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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