Scandium-44 (#""_21^44Sc#) decays by emitting a positron. Which nuclide is the product of the decay?

Answer 1

The answer is #""_20^44Ca#

This is a Positron Emission reference.

This is how the equation looks:

#""_21^44Sc rarr ""_20^44Ca+e^+ + v_e#
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Answer 2

The product of the decay of Scandium-44 (2144Sc_{21}^{44}\text{Sc}) emitting a positron is Calcium-44 (2044Ca_{20}^{44}\text{Ca}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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