One solution contains 55 g #NaCl # per liter. and another contains 55 g #KCl# per liter. Which solution has the higher molarity? How can you tell?
The quantity of material dissolved in one liter of solution is known as molarity.
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NaCl solution
- Since you're given the masses of each compound, all you have to do is to calculate its formula masses;
- After that, find the no. of moles of each compound using the formula:
number of mol=mass/formula mass
- Then find the Molarity(M) of each solution by using the formula
M=mol of solute/liters solution
- Compare the results per your calculation to determine which solution has higher M.
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It is obvious that there will be more sodium chloride solute particles if equal masses of the salts are added to the same volume because sodium chloride has a smaller molar mass.
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The molarity is the same for both solutions because it depends only on the number of moles of solute per liter of solution, regardless of the identity of the solute.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- 50.0 mL of a 0.269 M NaCl (aq) contain how many grams of solute?
- What is the concentration of a solution which contains 1 mole of #CaCl_2# dissolved in 2,000 milliliters of solution?
- Does solubility change with pressure?
- How does stirring affect the rate of solution formation?
- After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 milliliters of a new solution. How would this be prepared?
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