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Is the explosion of fireworks a physical or chemical change?

Answer 1

This is clearly an example of chemical change...........

The explosion of gunpowder in the air obviously satisfies the requirements for chemical change, which include the creation of new substances and the formation and breaking of strong chemical bonds.

Since everyone is now aware that gunpowder is a combination of sulfur, saltpeter, and charcoal, I can write a straightforward reaction to depict the gunpowder reaction as follows:

#8C(s) +10KNO_3(s) +3S(s)rarr6CO_2(g) + 5N_2(g) + 2K_2CO_3(s) +3K_2SO_4(s)#

Is this balanced? Do not trust my arithmetic. Clearly, strong chemical bonds have been broken, and stronger chemical bonds have been formed, most notably #C=O# and #N-=N# bonds, which provide a thermodynamic driving force for the reaction.

Can you imagine the risks associated with this research, and even more so with producing gunpowder for armaments? The accidents that have happened—and they will inevitably happen—have had horrifying outcomes.

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Answer 2

Peyton Adams

Fireworks explode because of a chemical shift.

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Answer 3

Cooper Anderson

The explosion of fireworks is a chemical change.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.