In the reaction #H_3A(s) + 3NaOH(aq) -> 3H_2O(l) + Na_3A(aq)#, if it takes 38.22 mL of .1665 M #NaOH# to neutralize .4750 g of the acid, what is the molar mass of the acid?
Here's what I got.
Start by writing down the balanced chemical equation for this neutralization reaction
This mole ratio will allow you to find the number of moles of acid present in solution.
Simply put, if you know how many moles of sodium hydroxide were needed to neutralize the acid, you can use this mole ratio to figure out how many moles of acid were present in solution.
So, you know the molarity and volume of the sodium hydroxide solution used in the reaction. The number of moles of sodium hydroxide will be equal to
This means that the solution must have contained
The molar mass of the acid will thus be
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The molar mass of the acid (H3A) is approximately 151.3 g/mol.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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