If the Hubble Space Telescope proved that Hubble's constant is actually half as large as it is currently believed to be, what would the implied age of the universe be in comparison to the current accepted value?

Question

Luke Allen · Accepted Answer

In appropriate units of time and distance, the reciprocal #1/H_o# of Hubble constant #H_o# gives the age of our universe. As the reciprocal of #H_o/2=2/H_o#, the age is doubled.

The dimension of Hubble constant, #[H_o]-LL^(-1)T^(-1)=T^(-1)#. The dimension of thr reciprocal #[1/H_o]=T# As of now, different estimates of #H_o# have a range around 70 km/s/mega parsec. After converting time to years and distances to units of measurement, the reciprocal is approximately 13.8 billion years.

Ariana Acosta · Answer

undefined The universe's implied age would be roughly twice as large as the currently accepted value if the Hubble Space Telescope demonstrated that Hubble's constant is, in fact, half as large as it is thought to be.