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If a rocket with a mass of #900 kg# vertically accelerates at a rate of # 2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 4 seconds?

Answer 1

Nora Arzate

Given #M->"Mass of rocket"=900kg# #a->"Acceleration"=2m/s^2#

#g->"Acceleration due to gravity"=9.8m/s^2#

#"Velocity after t sec "(v)=at#

#"Force applied"(F)=M(g+a)#

#"Power at t s"#

#P(t)=Fxxv=M(g+a)at#

Power #"at "t=4 s#

#P(4)=900xx(9.8+2)xx2xx4W#

#= 84.960kW"#

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Answer 2

Xavier Adame

To find the power exerted by the rocket, you can use the formula $P = F \cdot v$ , where $P$ is power, $F$ is force, and $v$ is velocity. The force exerted by the rocket can be calculated using Newton's second law: $F = m \cdot a$ , where $m$ is mass and $a$ is acceleration. Then, you need to calculate the velocity of the rocket at 4 seconds using the formula $v = u + at$ , where $u$ is initial velocity (assumed to be 0 m/s because it starts from rest), $a$ is acceleration, and $t$ is time. Finally, plug the values into the power formula to find the answer.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.