How would you draw the hydrogenation reaction 2-methyl-2-butene and name the product?

Question

Lucy Alessi · Accepted Answer

The product is 2-methylbutane.

Hydrogen adds to alkenes in the presence of catalysts like #"Pt"#, #"Pd"#, and #"Ni"#.

The equation for the hydrogenation of 2-methylbut-2-ene is

#underbrace(("CH"_3)_2"C=CHCH"_3)_color(red)("2-methylbut-2-ene") + "H"_2 stackrelcolor (blue)("Pt, Pd, or Ni")(→) underbrace(("CH"_3)_2"CH-CH"_2"CH"_3)_color(red)("2-methylbutane")#

The product has a chain of four carbon atoms with a methyl group on #"C-2"#, hence the name 2-methylbutane.

Easton Jones · Answer

undefined The hydrogenation reaction of 2-methyl-2-butene involves the addition of hydrogen gas (H2) across the double bond to form a saturated hydrocarbon. The product of this reaction is 2-methylbutane.

The balanced chemical equation for the hydrogenation reaction of 2-methyl-2-butene is:

2-methyl-2-butene + H2 ⟶ 2-methylbutane

To draw the reaction, you would represent the structure of 2-methyl-2-butene, which has a double bond between the second and third carbon atoms, and add hydrogen (H2) across the double bond to form 2-methylbutane, which is a straight-chain alkane with four carbon atoms and a methyl group attached to the second carbon atom.

Ryan Andrews · Answer

undefined To draw the hydrogenation reaction of 2-methyl-2-butene, start by sketching the structure of 2-methyl-2-butene, which consists of four carbon atoms in a chain with a methyl group (CH3) attached to the second carbon atom from either end, and a double bond between the second and third carbon atoms. Then, represent the addition of hydrogen (H2) across the double bond by adding two hydrogen atoms to each of the carbon atoms involved in the double bond. The product of this reaction would be 2-methylbutane.