How would you calculate the speed at which the earth revolves around the sun in m/s?

Answer 1

Calculate from the average distance of the Earth from the sun and the time it takes to complete one orbit as about #3xx10^4 ms^(-1)#

On average, the Earth is approximately 150 million kilometers away from the Sun, or 1.5 x 10^11 meters.

The orbit of the Earth around the sun is roughly circular (more eliptical really, but let's keep it simple), with a period of roughly #365# days.

So the path that the Earth traverses in #365# days is approximately the circumference of a circle of radius #1.5 xx 10^11m#.

Use the formula #C = 2pir# to find that this is about #9.4 xx 10^11m#.

The number of seconds in #365# days is:

#365 * 24 * 60 * 60 = 31536000#

Thus, the Earth's tangential velocity is roughly:

#(9.4 xx 10^11) / (3.1536 xx 10^7) ~~ 3 xx 10^4 m s^(-1)#

That is #30# km per second.

To achieve greater precision, obtain more precise measurements of Earth's perihelion and aphelion distances from the sun and utilize a more precise orbital period calculation.

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Answer 2

Ivy Allen

The speed at which the Earth orbits the Sun is about thirty kilometers per second (km/s), or thirty thousand meters per second (m/s), and is determined by dividing the circumference of the Earth's orbit by the time it takes to complete one revolution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.