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How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2

Answer 1

Avery Adams

How many grams of NaCl are produced if 80.0 grams of #O_2# are produced?

We begin with a balanced chemical equation that is provided in the question.

#2NaClO_3 -> 2NaCl + 3O_2#

Next we determine what we have and what we want.
We have 80.0 grams of Oxygen and we want grams of Sodium Chloride.

We set up a roadmap to solve the problem

#grams O_2 -> mol O_2 -> mol NaCl -> grams NaCl#

We need the molar mass (#gfm#) of #O_2# and #NaCl#.
#O_2# = 31.98 g/mol and #NaCl# = 58.44 g/mol.

We need the mole ratio between #O_2#:#NaCl# 3:2. This comes from the coefficients of the balanced chemical equation.

Now we set up conversion factors following the roadmap from above.
Unit we want in the numerator, unit to cancel in the denominator.

#80.0 g O_2 x (1 mol O_2)/(31.98 g O_2) x (2mol NaCl)/(3 mol O_2) x(58.44 g NaCl)/(1 mol NaCl) =#

Multiply the numerators, and divide the denominators.

The outcome is
#97.5 g NaCl#
will be produced with 80.0 grams #O_2#

I hope this was helpful.
SMARTERTEACHER

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Answer 2

Mateo Aguilar

To determine the number of grams of NaCl produced when 80.0 grams of O2 are produced, we first need to find the molar ratio between NaCl and O2 in the balanced chemical equation:

2 NaClO3 ---> 2 NaCl + 3 O2

From the equation, we see that 2 moles of NaCl are produced for every 3 moles of O2.

Next, we need to calculate the molar mass of O2:
Molar mass of O2 = 2 * 16.00 g/mol = 32.00 g/mol

Then, we calculate the number of moles of O2 produced using the given mass:
Number of moles of O2 = mass / molar mass = 80.0 g / 32.00 g/mol = 2.50 moles

Now, we use the molar ratio to find the number of moles of NaCl produced:
Number of moles of NaCl = (2.50 moles O2) * (2 moles NaCl / 3 moles O2) = 1.67 moles

Finally, we calculate the mass of NaCl produced using its molar mass:
Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol

Mass of NaCl produced = number of moles * molar mass = 1.67 moles * 58.44 g/mol ≈ 97.75 grams

Therefore, approximately 97.75 grams of NaCl are produced when 80.0 grams of O2 are produced.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---&gt; 2 NaCl + 3 O2

How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2