How many aluminium atoms are present in 5.396 grams of aluminium? 2Al + 6HCI -> 2AlCl3 + 3H2

Answer 1

Approx. #1.2xx10^23# individual aluminum atoms.

We must (i) determine the molar quantity.

#(5.396*g)/(26.982*g*mol^-1)=0.2000*mol#

And then (ii), multiply this molar quantity by #"Avogadro's number"#, #6.022xx10^23*mol^-1# to get...................................

#0.2*molxx6.022xx10^23=??#

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Answer 2

Peyton Adams

To find the number of aluminum atoms in 5.396 grams of aluminum, first calculate the number of moles of aluminum using its molar mass (26.98 g/mol). Then, use Avogadro's number (6.022 × 10^23 atoms/mol) to convert moles to atoms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How many aluminium atoms are present in 5.396 grams of aluminium? 2Al + 6HCI -&gt; 2AlCl3 + 3H2

How many aluminium atoms are present in 5.396 grams of aluminium? 2Al + 6HCI -> 2AlCl3 + 3H2