How do you solve #x (x^2 + 2x + 3)=4# by factoring?

Answer 1

First multiply out and write in standard polynomial form to obtain

#x^3+2x^2+3x-4=0#

This is now a 3rd degree cubic equation and has 3 roots.

We may use the remainder theorem, which involves first obtaining a single root by inspection, and then long dividing the corresponding factor into the cubic and then factorizing the resultant quadratic by factors.

Now if we let #f(x)=x^3+2x^2+3x-4#, then we may for example use Newton's method of root finding in numerical analysis to find the first root by inspection. Note that #f'(x)=3x^2+4x+3# Starting with initial value #x_0=0# for example, we obtain that #x_1=x_o-f(x_o)/(f'(x_0))=0--4/3=4/3# #x_2=x_1-f(x_1)/(f'(x_1))=4/3-f(4/3)/(f'(4/3))=4/3-(160/27)/(41/3)=332/369~=0,9#
Now since this is not an integer value, we cannot long divide #f(x)# by #(x - 0,9)# as we will battle to obtain factors.

So the best way will be to continue using Newton's method for the other 2 roots as well, and then rewrite the original polynomial in factor form like that.
I leave the details as an exercise :)

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Answer 2

To solve the equation x(x2+2x+3)=4x(x^2 + 2x + 3) = 4 by factoring, follow these steps:

  1. Expand the expression x(x2+2x+3)x(x^2 + 2x + 3) to get x3+2x2+3xx^3 + 2x^2 + 3x.
  2. Rewrite the equation as x3+2x2+3x4=0x^3 + 2x^2 + 3x - 4 = 0.
  3. Try to factor the expression x3+2x2+3x4x^3 + 2x^2 + 3x - 4 into linear factors.
  4. By inspection or using techniques like synthetic division or the rational root theorem, find a root (solution) of the equation.
  5. Once you find one root, use polynomial long division or synthetic division to divide the polynomial by the corresponding linear factor to find the remaining quadratic factor.
  6. Factor the quadratic factor (if possible) to find the other roots.
  7. Verify the solutions by substituting them back into the original equation.

This process should yield the solutions to the equation x(x2+2x+3)=4x(x^2 + 2x + 3) = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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