How do you solve #x − 6 = 11#?

Answer 1

#color(magenta)("x=17")#

#color(blue)("Add 6 to both sides of the equation. This will allow you to")# #color(blue)("get the variable (a letter that takes the place of an unknown"# #color(blue)("number) and the constant (a number) by themselves so you can solve for x:")#
#xcancel-6=11# #color(white)(aa)cancel+6 +6#
Now, on the left side you are just left with #x# since (-6)+6 = 0. On the right side you end up with 17 because 11+6 = 17.

Thus,

#color(blue)("x=17#
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Answer 2

To solve ( x - 6 = 11 ), you can add 6 to both sides of the equation to isolate x:

( x - 6 + 6 = 11 + 6 )

( x = 17 )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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