# How do you solve #sinx+2=3#?

see below

By signing up, you agree to our Terms of Service and Privacy Policy

To solve the equation sin(x) + 2 = 3, you first isolate the sine term by subtracting 2 from both sides. Then, you solve for sin(x) by subtracting 2 from 3, which equals 1. Finally, you find the angle whose sine is 1, which is π/2 or 90 degrees. So, the solution is x = π/2 + 2πn, where n is an integer representing additional solutions due to the periodic nature of the sine function.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you prove #cos^2β-sin^2β=2cos^2β-1#?
- How do you prove #(1+tany)/(1+coty)=secy/cscy#?
- How do you find all solutions of the equation in the interval #[0,2pi)# given #cos4x(cosx-1)=0#?
- How do you find the exact solutions of the equation #4sinxcosx=1# in the interval #[0,2pi)#?
- If #sectheta+tantheta=3/2#, what is the value of #sintheta#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7