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How do you graph the line #y=1/3x+3#?

Answer 1

Julia Adams

See a solution process below:

Plot the first two points that are found by solving the equation:

First Point: For #x = 0#

#y = (1/3 * 0) + 3#

#y = 0 + 3#

#y = 3# or #(0, 3)#

Second Point: For #x = 3#

#y = (1/3 * 3) + 3#

#y = 1 + 3#

#y = 4# or #(1, 4)#

Next, we can chart the two points on the coordinate plane as follows:

graph{ [-10, 10, -5, 5]} = (x^2+(y-3)^2-0.025)((x-3)^2+(y-4)^2-0.025)=0

To graph the line, we can now draw a straight line through the two points as follows:

graph{(x^2+(y-3)^2-0.025)((x-3)^2+(y-4)^2-0.025)=0 [-10, 10, -5, 5]}

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Answer 2

Abigail Allen

To graph the line y = (1/3)x + 3:

Plot the y-intercept at (0, 3).
Use the slope, which is 1/3, to find a second point. Since the slope is rise over run, go up 1 unit and right 3 units from the y-intercept.
Connect the two points with a straight line to graph the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.