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How do you find the six trigonometric functions of #(7pi)/6# degrees?

Answer 1

Zoe Austin

Trig unit circle:

#sin ((7pi)/6) = sin (pi/6 + pi) = -sin (pi/6) = -1/2 # (trig table)

#cos ((7pi)/6) = cos (pi/6 + pi) = - cos pi/6 = -(sqr3)/2#

#tan ((7pi)/6) = (1/2).(2/(sqr3)) = 1/(sqr3) = (sqr3)/3#

#cot ((7pi)/6) = sqr3#

#sec (7pi/6) = -2/(sqr3) = (-2sqr3)/3#

#csc (pi/6) = -2#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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