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How do you find the prime factorization of 20?

Answer 1

Zoe Adams

#20 = 2 xx 2 xx 5#

You can separate out each prime factor in turn as follows:

#20# is divisible by #2# (i.e. even) since its last digit is even.

So divide by #color(blue)(2)# to get #10#.

#10# is divisible by #2# since its last digit is even.

So divide by #color(blue)(2)# to get #5#.

#color(blue)(5)# is prime.

So we can stop and write down #20# as the product of the primes we have found:

#20 = 2 xx 2 xx 5#

This can be written as a factor tree:

#color(white)(00000)20# #color(white)(0000)"/"color(white)(00)"\"# #color(white)(000)color(blue)(2)color(white)(000)10# #color(white)(000000)"/"color(white)(00)"\"# #color(white)(00000)color(blue)(2)color(white)(0000)color(blue)(5)#

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Answer 2

Mila Anderson

To find the prime factorization of 20, you start by dividing 20 by the smallest prime number, which is 2.

20 ÷ 2 = 10

Since 10 is still divisible by 2:

10 ÷ 2 = 5

Now, 5 is a prime number, so we stop here.

The prime factorization of 20 is therefore 2 × 2 × 5, or written as powers of primes: 2^2 × 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.