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How do you find the area of #triangle ABC# given a=24, b=12, sinC=3/4?

Answer 1

Oliver Atkinson

# 108" sq.unit"#.

Trigonometry allows us to know that,

the Region of

#DeltaABC=1/2*a*bsinC=1/2*24*12*3/4=108" sq.unit"#.

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Answer 2

Aaliyah Abdullah

To find the area of triangle ABC given the side lengths a=24, b=12, and sinC=3/4, you can use the formula for the area of a triangle using side lengths and an angle:

Area = (1/2) * a * b * sin(C)

Substitute the given values into the formula:

Area = (1/2) * 24 * 12 * (3/4) Area = (1/2) * 24 * 12 * (3/4) Area = (1/2) * 24 * 12 * (3/4) Area = (1/2) * 24 * 12 * (3/4) Area = (1/2) * 24 * 12 * (3/4) Area = 216 square units

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.