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How do you find the amplitude, period, and shift for #y=sin (3x-pi/4)#?

Answer 1

#Amplitude =1#
#Period=(2pi)/3#
phase (shift) # = pi/4 # to the right

Let #y=asin(bx+c)# The amplitude is the coefficient #a# of the sine, here it is 1 The period depends on the coefficient b of x, So here we have #3# So the peroid #=(2pi)/3#, if the coefficient was 1, the period is #2pi# The phase shift depends on the value and sign of c: Here it is #-pi/4# So it is #pi/4# to the right

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Answer 2

Zoe Austin

Amplitude: 1, Period: ( \frac{2\pi}{3} ), Shift: ( \frac{\pi}{12} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.