How do you find the amplitude, period, and shift for #y= 4 sin(theta/2)#?
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For the function y = 4 sin(theta/2), the amplitude is 4, the period is 4π, and there is no horizontal shift.
The amplitude of a sine function determines the maximum displacement from the midline. In this case, the amplitude is 4, meaning the graph of the function will oscillate between -4 and 4.
The period of a sine function is the distance between two consecutive peaks (or troughs) of the graph. The period can be calculated using the formula 2π/b, where b is the coefficient of theta in the function. Here, b = 1/2, so the period is 2π / (1/2) = 4π.
Since there is no horizontal shift, the function is not shifted to the left or right on the graph. Therefore, the shift is 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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