How do you evaluate #abs(-64+7)+2-6#?

Answer 1

See a solution process below:

The absolute value function is treated like a set of parenthesis, so evaluate the term inside it first using the PEDMAS order of operations:

#abs(color(red)(-64) + color(red)(7)) + 2 - 6 =>#

#abs(-57) + 2 - 6#

After that, use the absolute value function, which takes any term and converts it to a non-negative form.

#color(red)(abs(-57)) + 2 - 6 =>#

#57 + 2 - 6#

Proceed with the Addition and Subtraction processes in a left-to-right manner.

#color(red)(57) + color(red)(2) - 6 =>#

#59 - 6 =>#

#53#

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Answer 2

Gianna Caruso

To evaluate $|(-64 + 7)| + 2 - 6$ , follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).

First, solve the expression inside the absolute value brackets: $-64 + 7 = -57$ .

Then, take the absolute value of $-57$ , which is $|-57| = 57$ .

Next, perform addition and subtraction: $57 + 2 - 6$ .

Finally, add and subtract in order: $57 + 2 = 59$ and $59 - 6 = 53$ .

So, $|(-64 + 7)| + 2 - 6 = 53$ .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.