How do you convert #x^2 + y^2 = 4x# into polar form?
Emery AdkinsIt is
We can rewrite this using the following transformation
so we have that
#r^2cos^2(theta)+r^2sin(theta)-4rcos(theta)=0=> r[rcos^2(theta)+rsin^2(theta)-4cos(theta)]=0=> [r(cos^2(theta)+sin^2(theta))-4cos(theta)]=0=> r=4cos(theta)#
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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