# How do you convert #x^2 + y^2 = 4x# into polar form?

It is

We can rewrite this using the following transformation

so we have that

#r^2*cos^2(theta)+r^2*sin(theta)-4r*cos(theta)=0=>
r*[r*cos^2(theta)+r*sin^2(theta)-4*cos(theta)]=0=>
[r*(cos^2(theta)+sin^2(theta))-4cos(theta)]=0=>
r=4cos(theta)#

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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