# How do I simplify #sin^4x-2sin^2x+1#?

It is a perfect square:

By signing up, you agree to our Terms of Service and Privacy Policy

So,the given expression becomes,

By signing up, you agree to our Terms of Service and Privacy Policy

By signing up, you agree to our Terms of Service and Privacy Policy

To simplify ( \sin^4(x) - 2\sin^2(x) + 1 ), you can use the identity ( \sin^2(x) = 1 - \cos^2(x) ).

Replace ( \sin^2(x) ) with ( 1 - \cos^2(x) ):

[ \sin^4(x) - 2(1 - \cos^2(x)) + 1 ]

Expand and simplify:

[ \sin^4(x) - 2 + 2\cos^2(x) + 1 ]

Combine like terms:

[ \sin^4(x) + 2\cos^2(x) - 1 ]

This is the simplified form of ( \sin^4(x) - 2\sin^2(x) + 1 ).

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you prove that #(1 + tan theta)[1 + tan(1/4 pi - theta)] = 2#?
- How do you find the value of #cos((7pi)/8)# using the double or half angle formula?
- How do you solve (cscx-cotx)^4(cscx+cotx)^4=1?
- How to use the product-to-sum formula to write the product as a sum or difference? 4 cos pi/3 sin 5pi/6
- How do you simplify #Tan(x) Csc(x)/sec(x)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7