How can I draw the axial and equatorial bonds in a cycloctane?

To satisfy the octet rule for the carbon atoms, each of the eight carbons in a molecule of cyclooctane will have two hydrogens attached: one axial and one equatorial. The axial carbons are straight up and down (in a flat ring, they will point straight up and down, alternating on each carbon; up, down, up, down, etc.), and the equatorial hydrogens are 109.5* up or down from the axial carbons.

For instance, if the axial bond is drawn on carbon number 1 with the axial bond pointing straight up, the equatorial bond will be to the side of that carbon, pointing slightly down; if the axial bond is drawn on carbon number 2 of the same ring with the equatorial bond to the side and slightly up.

To draw the axial and equatorial bonds in a cyclooctane, start by drawing the cyclooctane ring structure. Then, for each carbon atom in the ring, alternate between placing bonds pointing up (axial bonds) and bonds pointing down (equatorial bonds) to represent the axial and equatorial positions, respectively. Ensure that each carbon atom has four bonds, maintaining the tetrahedral geometry of carbon.