Given the Following: heat of fusion of ice = 80.0 cal/g; specific heat of ice = 0.480 cal/g; and specific heat of water = 1.00 cal/g. Calculate the amount of heat required to melt 30.0 g of ice at 0 degrees celsius?
We wish to assess the enthalpy change for the physical reaction......
In the same vein, we would report the reverse reaction's enthalpy change.
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To calculate the amount of heat required to melt 30.0 g of ice at 0 degrees Celsius, we need to consider two steps: first, we need to heat the ice from 0°C to its melting point, and then we need to melt the ice.
- Heat required to raise the temperature of ice from 0°C to its melting point:
q1 = mass × specific heat of ice × temperature change
= 30.0 g × 0.480 cal/g°C × (0°C - 0°C)
= 0 cal
- Heat required to melt the ice:
q2 = mass × heat of fusion of ice
= 30.0 g × 80.0 cal/g
= 2400 cal
Therefore, the total heat required is:
Total heat = q1 + q2
= 0 cal + 2400 cal
= 2400 cal
So, 2400 calories of heat are required to melt 30.0 g of ice at 0 degrees Celsius.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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