Given f(x)=x²+3x-5 and g(x)=2x-3, how do you determine x when f(x)=g(x)?

Answer 1

To determine the value of ( x ) when ( f(x) = g(x) ), you set the two functions equal to each other and solve for ( x ). In this case:

[ f(x) = g(x) ] [ x^2 + 3x - 5 = 2x - 3 ]

Then, you rearrange the equation and solve for ( x ):

[ x^2 + 3x - 5 - 2x + 3 = 0 ] [ x^2 + x - 2 = 0 ]

Now, you can use methods like factoring, completing the square, or the quadratic formula to solve for ( x ).

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Answer 2

The solutions are #S={-1,2}#

#f(x)=x^2+3x-5#
#g(x)=2x-3#
#f(x)=g(x)#
#x^2+3x-5=2x-3#
#x^2-x-2=0#

By factorization, we are able to solve this quadratic equation.

#(x+1)(x-2)=0#
#x-1=0#, #=>#, #x=-1#
#x-2=0#, #=>#, #x=2#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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