Determine the rate law and rate constant for reaction detailed below?

The decomposition of ethanol (#C_2H_5OH#), catalyzed by the presence of a metal surface, was studied at 600 K. Concentration versus time data were collected for this reaction, and a plot of #[C_2H_5OH]# versus time resulted in a straight line with a slope of #-4.00xx10^-5# mol/L sec.

Answer 1

a. #\tt{k=4.00xx10^-5mol//L*sec}#
b. #\tt{rate_(rxn)=k}#

1. Concentration vs time being linear: #\sf{"zero-order"}# because this corresponds to the integrated rate law given by:

#tt([A] = -kt + [A]_0)#

and because its slope has the same units as the rate of reaction. That can only mean #tt([A]^m = 1)#, i.e. #tt(m = 0)# in the rate law.

2. Zero-order rate constant #\tt{k}# is negative slope, so:

#\tt{-overbrace(-4.00xx10^-5)^"slope" = k = 4.00xx10^-5}#

Considering a zero-order rate law, therefore,

#\tt{rate_(rxn)=k[C_2H_5OH]^0=k}#

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Answer 2

Cameron Andrews

To determine the rate law and rate constant for a reaction, experimental data is typically required. This data includes the initial concentrations of reactants, as well as the rates of reaction measured under those conditions. With this information, various methods such as the method of initial rates or graphical analysis can be used to determine the rate law and rate constant. Without specific experimental data for the reaction in question, it's not possible to provide the rate law and rate constant. Therefore, please provide the relevant experimental data, and I will assist you further in determining the rate law and rate constant for the reaction.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.