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A projectile is shot from the ground at an angle of #pi/8 # and a speed of #1 m/s#. When the projectile is at its maximum height, what will its distance from the starting point be?

Answer 1

Leo Abeyta

#t=0,04" "s"#
#X=v_i*t*cos alpha=0,036 " m"#

#t=0,04" "s"#
#"2- "X=v_i*t*cos alpha=0,036 " m"#

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Answer 2

Olivia Askew

Use the range formula for projectile motion:

[ R = \frac{u^2 \sin(2\theta)}{g} ]

where ( R ) is the range, ( u ) is the initial speed, ( \theta ) is the launch angle, and ( g ) is the acceleration due to gravity.

Given: ( u = 1 ) m/s ( \theta = \frac{\pi}{8} ) ( g = 9.8 ) m/s²

Find the range (( R )).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.