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A projectile is shot from the ground at an angle of #pi/8 # and a speed of #1 m/s#. When the projectile is at its maximum height, what will its distance from the starting point be?

Answer 1

Leo Abeyta

#t=0,04" "s"#
#X=v_i*t*cos alpha=0,036 " m"#

#t=0,04" "s"#
#"2- "X=v_i*t*cos alpha=0,036 " m"#

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Answer 2

Olivia Askew

Use the range formula for projectile motion:

$R = \frac{u^2 \sin(2\theta)}{g}$

where $R$ is the range, $u$ is the initial speed, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity.

Given:
$u = 1$ m/s
$\theta = \frac{\pi}{8}$
$g = 9.8$ m/s²

Find the range ( $R$ ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.