# A projectile is shot from the ground at a velocity of #15 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

The time is

We apply the equation of motion

Therefore,

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To determine the time of flight, use the projectile motion formula: ( \text{time} = \frac{2 \times \text{initial velocity} \times \sin(\text{launch angle})}{\text{acceleration due to gravity}} )

Substitute the values: ( \text{time} = \frac{2 \times 15 \times \sin\left(\frac{5\pi}{12}\right)}{9.8} )

Calculate to find the time of flight.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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