A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #4 m#. If the train's kinetic energy changes from #16 j# to #0 j#, by how much will the centripetal force applied by the tracks change by?

Answer 1

#8# Newtons

The train's speed before and after the kinetic energy change can be found using the following kinetic energy formula:

#v=sqrt((2E)/m)# #-> v = sqrt((2*16)/2)=sqrt(16)=4#
So we know the train was travelling at #4 ms^-1#
The kinetic energy at the end is #0J# so the train has obviously came to rest.
The centripetal force required at #4ms^-1#:
#F = (mv^2)/r# #-> F =(2*(4^2))/4=8N#
And the centripetal force required when the train is at rest is just #0N#. Thus the change in change in centripetal force is #8-0=8N#
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Answer 2

The centripetal force applied by the tracks will change by 16 Newtons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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