# A container with a volume of #25 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #320 ^o K# without any change in pressure, what must the container's new volume be?

Pressure, number of moles and Gas constant are all fixed.

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Using the combined gas law, ( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} ), and given that pressure remains constant:

( \frac{V_2}{V_1} = \frac{T_2}{T_1} )

Plugging in the values:

( \frac{V_2}{25, \text{L}} = \frac{320, \text{K}}{150, \text{K}} )

( V_2 ≈ \frac{320, \text{K}}{150, \text{K}} \times 25, \text{L} )

( V_2 ≈ 53.33, \text{L} )

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