A circuit with a resistance of #6 Omega# has a fuse that melts at #8 "A"#. Can a voltage of #66 "V"# be applied to the circuit without blowing the fuse?

Answer 1

Yes, a voltage of 66 V can be applied to the circuit without blowing the fuse. Using Ohm's Law (V = IR), we can calculate the current flowing through the circuit when a voltage of 66 V is applied:

$V = IR$
$66 = I \times 6$
$I = \frac{66}{6}$
$I = 11 A$

Since the current flowing through the circuit (11 A) is less than the melting point of the fuse (8 A), the fuse will not blow when a voltage of 66 V is applied.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

William Audy

Yes

By Ohm's law, the current flowing through is given by #I=V/R#.

#frac{66 "V"}{6 Omega} = 11 "A" > 8 "A"#

The fuse is going to melt.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.