What mass of sodium hydroxide do I need to neutralize 500 mL of 1 mol/L pamoic acid?
You need 40 g of
Assuming that pamoic acid is that soluble, here's how you would do the calculation.
Then the equation for the neutralization is
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The molar mass of pamoic acid is 517.6 g/mol. Therefore, you would need 0.5176 moles of pamoic acid to neutralize 500 mL of it. As sodium hydroxide reacts with pamoic acid in a 1:1 ratio, you would need 0.5176 moles of sodium hydroxide. The mass of sodium hydroxide required is 23.0 g.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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